Today Wednesday, June 5, 2024 is ...
Day 157
Day of the year is a number between 1 and 366 (in 2024), January 1 is day 1.2024 is a leap year.
After today 209 days are remaining in this year.
This page uses the ISO-8601 ordinal date format.
There is also another less-used format: the 'ISO day of year' numbers, this is a number between 1 and 371, day 1 of the year is Monday of the first ISO week (where the first Thursday of the new year is in week 1).
Lists of day numbers by year:2023 -2024 -2025 -2026 ...
Programming routines
Microsoft Excel
Calculate today's day-number, starting from the day before Jan 1, so that Jan 1 is day 1.
=TODAY()-DATE(YEAR(TODAY()),1,0)or, for any date entered in cell A1, calculate the corresponding day-number in that date’s year:=A1-DATE(YEAR(A1),1,0)
Google Docs Spreadsheet
=DATEDIF(CONCAT("1-1-";year(now()));today();"D")+1
Calculates the difference between Jan 1 and today (=days past) then add 1 for today's daynumber.(Your date format (1-1-year) may be different)
LibreOffice Calc:
=ROUNDDOWN(DAYS(NOW(),DATE(YEAR(NOW()),1,1))) + 1
PHP
$dayNumber = date("z") + 1;
You can use an epoch to find other day numbers:
date("z", epoch) + 1
date("z") starts counting from 0 (0 through 365)!
Python
from datetime import datetimeday_of_year = datetime.now().timetuple().tm_yday
PERL
use Time::Piece;my $day_of_year = localtime->yday + 1;# ... or ...my $day_of_year = (localtime)[7] +1;# ... or (if you really want to use POSIX) ...use POSIX;my $day_of_year = POSIX::strftime("%j", time);
Replace time with other epochs for other days.
MySQL
SELECT DAYOFYEAR(NOW())
Day number between 1 and 366. Replace now() with other dates eg.:
SELECT DAYOFYEAR('2024-02-20');
Oracle
select to_char(sysdate, 'DDD') from dualselect to_char(to_date('2024-02-20','YYYY-MM-DD'), 'DDD') from dual
Delphi
using DateUtils, SysUtils;DayOfTheYear(Date);
Microsoft Access
DatePart("y", Now())
Visual Basic (VB.NET)
Dim dayOfYear As Integer = DateTime.Now.DayOfYear
JavaScript
var today = new Date();Math.ceil((today - new Date(today.getFullYear(),0,1)) / 86400000);
Or add a 'Day of Year' method to the date object:
Date.prototype.getDOY = function() { var onejan = new Date(this.getFullYear(),0,1); return Math.ceil((this - onejan) / 86400000);}var today = new Date();var daynum = today.getDOY();
Java
LocalDate.now().getDayOfYear();
Unix/Linux
date +%j
ColdFusion
#dayofyear(now())#
Objective C
int currentDay;dateFormatter = [[NSDateFormatter alloc] init];[dateFormatter setDateFormat:@"D"];date = [NSDate date];currentDay = [[dateFormatter stringFromDate:date] intValue];
C++
Read the comment below by Mmars.
C#
int iDayOfYear = System.DateTime.UtcNow.DayOfYear;
R
format(Sys.Date(), "%j")
Ruby
time = Time.newputs time.yday
Powershell
$DayOfYear = (Get-Date).DayofYearWrite-Host $DayOfYear
LiveCode
on mouseUpput "January 1," && the last word of the long date into firstDayofYear --append current yearconvert firstDayofYear to seconds -- from Jan 1, 1970 to first day of this yearput the long date into currentDayconvert currentDay to seconds -- from Jan 1, 1970 GMT to todayput currentDay - firstDayofYear into totalSecondsanswer the round of (totalSeconds / (60*60*24)) + 1 --display total days in dialog boxend mouseUp
Or:
on mouseUpanswer DayOfYear()end mouseUpfunction DayOfYearput the short date into currentDateconvert currentDate to dateItems --list of date elements separated by commasput item 1 of currentDate into yearput item 2 of currentDate into monthput item 3 of currentDate into dayput floor (275 * month / 9) into N1put floor ( (month + 9) / 12) into N2put (1 + floor ( (year - 4 * floor (year / 4) + 2) / 3) ) into N3put N1 - (N2 * N3) + day - 30 into Nreturn Nend DayOfYearfunction floor pNumber -- LiveCode has no built-in floor() functionput Round (pNumber) into theIntegerif theInteger > pNumber thenput theInteger - 1 into theIntegerend ifreturn theIntegerend floor
T-SQL (Transact-SQL)
SELECT DATEPART(DAYOFYEAR, SYSDATETIME())
or
SELECT datediff(day,CAST(datepart(year,getdate()) AS CHAR(4)) + '-01-01',getdate()+1) AS number_of_today
Go (golang)
day := time.Now().YearDay()
Matlab
dayNumber = today-datenum(['1-Jan-' year(today)])+1
Powerbuilder
Read the comment below by Danny Cruz.
Thanks to all the developers who contributed to this page! (read comments below)